NPTEL Data Science for Engineers Assignment 4 Answers 2023? In this article we will discuss about the answers for Week 4 assignment of Data science for Engineers. All these answers are make it as reference.I am confident in providing these answers.
Also Read:Â NPTEL Data Science for Engineers Assignment 3 Answers 2023Â Â
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NPTEL Data Science for Engineers Assignment 4 Answers 2023Â
Last Date: 22-02-2023
You can find the answers for Data Science for Engineers Assignment 4 Answers 2023 below
Q1. Let f(x)=x^3+6x^2−3x−5. Select the correct options from the given options below :Â
a. −2+√5 will give the maximum for f(x).
b. −2+√5 will give the minimum for f(x).Â
c. The stationary points of f(x) are −2+√5 and −2+√5Â
d. The stationary points of f(x) are -4 and 0
Answer: [ c , b ]Â Â
        Reason : f '' (x) at  −2+√5 is > 0. Hence, it is called as local minima.Â
Solution:Â
       To find the stationary points of f(x), we need to find the values of x where f'(x) = 0.
f(x) = x^3 + 6x^2 - 3x - 5
f'(x) = 3x^2 + 12x - 3
Consider f'(x) = 0, we get:Â Â 3x^2 + 12x - 3 = 0
Dividing on both sides by 3:Â x^2 + 4x - 1 = 0
Using the quadratic formula, we get:
x= -b ± sqrt(4*a*c - 2*a)
x = (-4 ± sqrt(16 + 4))/2 = (-4 ± sqrt(20))/2
x = -2 ± sqrt(5)
So the stationary points of f(x) are -2 + sqrt(5) and -2 - sqrt(5).Â
To determine whether each point is a maximum or minimum, we need to look at the sign of f''(x) at each point.
f''(x) = 6x + 12
At x = -2 + sqrt(5), we have,
f''(-2 + sqrt(5)) = 6(-2 + sqrt(5)) + 12 = -6 + 6sqrt(5) > 0
So -2 + sqrt(5) is a local minimum.
At x = -2 - sqrt(5), we have,
f''(-2 - sqrt(5)) = 6(-2 - sqrt(5)) + 12 = -6 - 6sqrt(5) < 0
So -2 - sqrt(5) is a local maximum.
From the following information given below, answer the below questions Q2 and Q3.
Consider the following Optimization problem.Â
                             maxxϵRf(x) , where
                  f(x)=x^4+7x^3+5x^2−17^x+3
Let x∗ be the maximizer of f(x)
Q2. What is the second order sufficient condition for x∗ to be the maximize of the function f(x)?Â
a. 4x^3 + 21x^2 + 10x - 17 = 0
b. 12x^2 + 42x + 10 = 0
c. 12x^2 + 42x + 10 > 0
d. 12x^2 + 42x + 10 < 0Â
Answer:Â [ c]Â Â 12x^2 + 42x + 10 > 0Â
Solution:Â
        Â
Q3. Find the value of x*
a. -4.48
b. 0.66
c. -1.43
d. 4.45
Answer:Â [ c ] -1.43Â Â
Q4. Let f(x) = 2Sin x , 0≤x≤2Ï€ . Select the correct the options from the given following .Â
a. π/2 is the global maximum of f(x).
b. Ï€ is the global minimum of f(x).Â
c. 3Ï€/2 is the global maximum of f(x).Â
d. 3Ï€/2 is the global maximum of f(x).Â
Answer:Â [ a, d ]Â Â
Using the following information answer the following questions Q5, Q6, Q7,Q8.Â
Let f(x) = 2x1^2 + 3x1x2 + 3x2^2 + x1 + 3x2
Q5. Find the gradient of f(x).Â
Conclusion:
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